The 100-kg cylinder rolls without slipping on the horizontal plane. Determine the acceleration of its mass center.
what class btw?
I’m in favor of “the fluff roller” being a regular tool.
Just an old fashioned rolling pin will do fine.
dynamics
yuck
Im guessing you took ‘show your work’ IiteraIIy… Some kind of math probIem.
Dynamics is the reason I’m not an engineering student anymore. I swear I had the same problem on my final exam.
I had a moment of inspiration and wanted to make a shit edit of this with him saying ‘Get to the choppa’ and giving them a gun and pointing to a helicopter behind him.
But im also feeling out of energy. 
I might join you on that path if my semester grades go to shit
Preping for the MCAT at this moment. Let me try solve it.
So we know Fnet=ma. Friction goes in the opposite direction as Force Applied P, which means P-fricton=ma
Friction used here is rotational inertia x rotational acceleration
Rotational inertia = 1/2 mr^2
Torque = Rotational Inertia x Rotational Acceleration= 1/2 mr^2 x rotational acceleration = 1/2 mr^2 x a / r = 1/2mr x a
Torque = Friction x r = 1/2mr x a
Friction = 1/2ma
Thus F=ma=P-friction=P-1/2 ma
P=3/2ma = 3/2x 100 x a = 200N
150a = 200N a=1.33
correct me if I got anything wrong here!
Yeah that’s what I was gonna say
You are correct!! As reward for solving this, Imma let you choose a fluffy art style you want me to use for my next dynamics problem
Called it
Love2hatefluffs style would be neat.
Do you mind do more slopes and / or kinetic potential energy questions?
